/* Nathan DeBardeleben - ndebard@parl.clemson.edu
 * ECE 329
 * Test program for thread project.  This is very simple
 * and the only real change over Dr. Ligon's test program is
 * that this one will call thread exit.  You should find that
 * all 5 threads (main and 4 others) start up and then task1
 * dies, then task3 and then task4.  This will leave only 
 * main and task2 alternating. */

#include <stdio.h>

int task1();
int task2();
int task3();
int task4();

int main(int argc, char **argv)
{
	int i;
	if(thread_init() < 0) {
		fprintf(stderr,"Error initializing threads.\n");
		exit(1);
	}
	if(thread_create(task1, 1) < 0) {
		fprintf(stderr,"Error starting task 1.\n");
		exit(1);
	}
	if(thread_create(task2, 2) < 0) {
		fprintf(stderr,"Error starting task 2.\n");
		exit(1);
	}
	if(thread_create(task3, 3) < 0) {
		fprintf(stderr,"Error starting task 3.\n");
		exit(1);
	}
	if(thread_create(task4, 4) < 0) {
		fprintf(stderr,"Error starting task 4.\n");
		exit(1);
	}
	while(1) {
		printf("MAIN THREAD\n");
		for(i=0; i<5000000; i++) ;
	}
	thread_exit();
	return 0;
}

int task1()
{
	int i;
	for(i=0; i<2000; i++) 
		printf("\t[%d] THREAD 1\n", i);
	thread_exit();
}

int task2()
{
	int i;
	while(1) printf("\t\tTHREAD 2\n");
	thread_exit();
}

int task3()
{
	int i;
	for(i=0; i<3000; i++) 
		printf("\t\t\t[%d] THREAD 3\n", i);
	thread_exit();
}

int task4()
{
	int i;
	for(i=0; i<4000; i++) 
		printf("\t\t\t\t[%d] THREAD 4\n", i);
	thread_exit();
}