ECE 201; HW solutions for 3rd Edition; Chapter 2
P1
P2
a
xy + xy¢ = x(y+y¢) = x(1) = x
b
(x+y)(x+y¢) = x + yy¢ = x + 0 = x
c
xyz + x¢y + xyz¢
xy(z+z¢) + x¢y
xy + x¢y = (x+x¢)y = y
(A+B)¢(A¢+B¢)¢
A¢B¢AB = AA¢BB¢
0
P4
a
A¢C¢+ ABC + AC¢
(A¢+A)C¢+ ABC
C¢+ ABC
(C¢+C)(C¢+AB)
C¢+ AB
(x¢y¢+z)¢+ z + xy + wz
(x¢y¢+z)¢+ z + xy by absorption
(x+y)z¢+ z + xy by DeMorgan's
((x+y)+z)(z¢+ z) + xy
x+y+z + xy
x+y+z by absorption
c
A¢B(D¢+C¢D)+B(A+A¢CD)
B[A¢(D¢+C¢D)+(A+A¢CD)]
B[A¢(D¢+C¢)(D¢+D)+(A+A¢)(A+CD)]
B[A¢(D¢+C¢)+ A+CD]
B[A¢D¢+A¢C¢+ A+CD]
B[A¢D¢+(A¢+A)(C¢+A)+CD]
B[A¢D¢+C¢+A +CD]
B[A¢D¢+ A + (C¢+C)(C¢+D)]
B[A¢D¢+ A + C¢+D]
B[(A¢+ A)(D¢+A) + C¢+D]
B[D¢+A + C¢+D]
B(A + C¢+ 1)
B(1) = B
P6
Find the complement of the following expressions:
a
(xy¢+x¢y)¢ = (x¢+y)(x+y¢)
b
((AB¢+ C)D¢+E)¢
((A¢+B)C¢+D)E¢
c
[ (x+y¢+z)(x¢+z¢)(x+y) ]¢
x¢yz¢+ xz + x¢y¢
P8
List the truth table of the function:
F = xy + xy¢+ y¢z
P14
*
a
(xy+z)(y+xz)
F = S(3,5,6,7)
F = P(0,1,2,4)
b
(A¢+B)(B¢+C)
F = S(0,1,3,7)
F = P(2,4,5,6)
c
y¢z + wxy¢+ wxz¢+ w¢x¢z
F = S(1,3,5,9,12,13,14)
F = P(0,2,4,6,7,8,10,11,15)
P15
F = xy¢z + x¢y¢z + w¢xy + wx¢y + wxy
a
F = xy¢z + x¢y¢z + w¢xy + wx¢y + wxy
F = (x+x¢)y¢z + (w¢+w)xy + wx¢y
F = y¢z + xy + wx¢y
F = y¢z + (x + wx¢)y
F = y¢z + (x + w)y
P16
F(A,B,C,D) = B¢D + A¢D + BD
F = (A+A¢)B¢(C+C¢)D + A¢(B+B¢)(C+C¢)D + (A+A¢)B(C+C¢)D
F(SOM) = A¢B¢C¢D + A¢B¢CD + AB¢C¢D + AB¢CD + A¢B¢C¢D + A¢B¢CD + A¢BC¢D+ A¢BCD + A¢BC¢D + A¢BCD + ABC¢D + ABCD
F(SOM) = S(1,3,5,7,9,11,13,15)
F(POM) = P(0,2,4,6,8,10,12,14)
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On 17 Sep 2001, 08:54.